Homework Explained - Math Practice 101

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Grade 8 McGraw Hill Glencoe - Answer Keys


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  • Question 8 (request help)

    Construct an Argument In the figure at the right, AE = DB and C is the midpoint of \(\overline{\text{AE}}\) and \(\overline{\text{DB}}\). Complete the proof to show that AC = CB.

    Given: AE = DB and C is the midpoint of \(\overline{\text{AE}}\) and \(\overline{\text{DB}}\)

    Prove: AC = CB

    Proof: Since C is the midpoint of _____ and _____, AC = CE = \(\cfrac{1}{2}\) _____ and DC = CB = \(\cfrac{1}{2}\) _____ by the definition of midpoint. We are given AE = DB. By the _____ Property of Equality, \(\cfrac{1}{2}\)AE = \(\cfrac{1}{2}\)DB. So, by _____, AC = CB.

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  • Question 9 (request help)

    Construct an Argument Refer to the figure at the right. Complete the two-column proof to show if m∠3 = 2x - 15 and m∠6 = x + 55, then x = 70.

    Given: j || k, transversal l; m∠3 = 2x - 15, m∠6 = x + 55

    Prove: x = 70

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  • Question 10 (request help)

    Construct an Argument Refer to the figure at the right. Complete the two-column proof to show if ∠ABE and ∠DBC are right angles, then m∠ABD = m∠EBC.

    Given: ∠ABE and ∠DBC are right angles

    Prove: m∠ABD = m∠EBC

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